Contoh Soal Beban Merata

Friday, April 19, 2013




Jawaban :

∑ H = 0
HA – 4 cos 45⁰ = 0
HA = 4 . ½ √2
      = 2√2
      = 2,8284 t

∑MA = 0
2(2) + 12(3) + 3(4) + 4 sin 45⁰ (9) – VB (6) = 0
6 VB = 4 + 36 + 12 + 2√2 (9)
6 VB = 52 + 25,4556
6 VB = 77,4556
VB    = 12,909 t

∑MB = 0
VA (6) – 2(4) – 12(3) – 3(2) + 4 sin 45⁰ (3) = 0
6 VA = 8 + 36 + 6 - 2√2 (3)
6 VA = 50 – 8,4852
6 VA = 41,5148
VA    = 6,9191 t

Bukti :
∑V = 0
VA + VB – 2 – 12 – 3 – 4 sin 45⁰ = 0
6,9191 + 12,909 = 2 + 12 + 3 +2,8284
19,828 t = 19,828 t
OK !
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